m^2+13m-4=2

Solution for m^2+13m-4=2 equation:

m^2+13m-4=2

We move all terms to the left:

m^2+13m-4-(2)=0

We add all the numbers together, and all the variables

m^2+13m-6=0

a = 1; b = 13; c = -6;
Δ = b2-4ac
Δ = 132-4·1·(-6)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{193}}{2*1}=\frac{-13-\sqrt{193}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{193}}{2*1}=\frac{-13+\sqrt{193}}{2}
$